To solve this system by the addition method, we simply add the 2 equations. However, we want to eliminate a variable (lets choose x), so we must multiply the top equation by 2
2(5x – 3y) = 2(3)
-10x + 6y = -4
Distribute the 2
10x – 6y = 6
-10x + 6y = -4
Now add the like terms of the 2 equations. For instance we'll add 10x and -10x to get . Do this for every like term
(10x+(-10x)) + (6y+(-6y)) = 6+(-4)
0x + 0y = 2
So we get
0=2
which is not true. So this means for any x we choose, this system will never be satisfied. So there are no solutions