SOLUTION: Determine the x-intercept, the vertex, the direction of opening and the domain/range.
x=(x+6)(2x-5)
The only thing I know is that the y-intercept is -30 because I expanded it
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Question 776955: Determine the x-intercept, the vertex, the direction of opening and the domain/range.
x=(x+6)(2x-5)
The only thing I know is that the y-intercept is -30 because I expanded it into
x= 2x^2 + 7x - 30 and that it opens upward because 2x^2 is postive
I haven't done Math in months, so I'm completely stomped on these review questions
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Your terminology is incorrect. -30 is NOT the 
-intercept. -30 is the -coordinate of the -intercept. The -intercept is the point )
The 
-coordinate of the vertex of \ =\ ax^2\ +\ bx\ +\ c)
is given by 
. The -coordinate of the vertex is the value of the function at the vertex -value, or )
. Just plug in your numbers and do the arithmetic.
The -intercepts are the points )
and )
where 
and 
are the zeros of the function. These should be obvious because you started with the function already factored.
You are correct about the direction of opening.
This is a polynomial function so the domain is all real numbers. The range is the interval [,\,\infty)
)
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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