SOLUTION: I can not find an answer to this, I tried to factor but that did not turn out right. Please help. (x+4)/(6x^2+5x-6)+(x)/(2x+3)= (x)/(3x-2)

Question 7751: I can not find an answer to this, I tried to factor but that did not turn out right. Please help.
(x+4)/(6x^2+5x-6)+(x)/(2x+3)= (x)/(3x-2)
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Ok, here we go!
Factor the denominator of the 1st fraction.
Add the two fractions on the left side. Common denominator is (2x+3)(3x-2), so multiply the 2nd fraction by (3x-2)/(3x-2)
Add 'em up.
Simplify the left side.
Multiply both sides by (3x-2)
Multiply both sides by (2x+3)
Simplify and set equal to zero.
Solve the quadratic equation by factoring.
Apply the zero product principle.
x-2 = 0, then x = 2
The solution is: a double root; x = 2
Check:

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