SOLUTION: Trying to find the line prependicular to 3/4x-1. The reciprocal for the slope is -4/3x. Placed the given point (4,0) and the slope into the point slope form of a linear equation

Question 756089: Trying to find the line prependicular to 3/4x-1. The reciprocal for the slope is -4/3x. Placed the given point (4,0) and the slope into the point slope form of a linear equation y-y1=m(x-x1) and get -4/3x+16/3. I'm stuck after that. Do I make the improper fraction a mixed number of leave it improper? Help please
Found 2 solutions by josmiceli, josgarithmetic:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

Slope of perpendicular is
Goes through ( 4,0 )
Using point-slope formula:

Multiply both sides by

That's it- it's as complete as you can get it.
Good job

Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
Not important unless instructions tell you one way or another. Make your final form readable. Put into either standard form of slope intercept form to finish.

You need to simplify from this form:
Continue as,

which is in slope-intercept form and at least symbolically, simplified. No matter having fractions or not, you want to put into either slope intercept form OR standard form, so that you have the expected identifiable terms.

The description you gave for your process is good.
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