SOLUTION: Find the standard form for the equation of the line which passes through the point (-1,-2) and is parallel to the line whose equation is 6x+2y=4?

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Question 74978: Find the standard form for the equation of the line which passes through the point (-1,-2) and is parallel to the line whose equation is 6x+2y=4?
Answer by funmath(2933)   (Show Source): You can put this solution on YOUR website!
Find the standard form for the equation of the line which passes through the point (-1,-2) and is parallel to the line whose equation is 6x+2y=4?
Parallel lines have equal slopes, so our line has the same slope as 6x+2y=4.
To find the slope of the equation of a line, put the line in slope-intercept form: , where m=slope and (0,b)=y-intercept




The slope is, m=-3
Therefore, our line has a slope of m=-3 and goes through the point (-1,-2).
Some teachers use the slope intercept form of a line to find b and make the equation.
Others use the point-slope formula (my preference): , where m=slope and (x1,y1)=given point.
(x1,y1)=(-1,-2) and m=-3



The standard form of a line is , where A,B, and C are integers and most books and teachers prefer that A be positive.




Happy Calculating!!!!

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