SOLUTION: Find the equation of the line that goes through the point (-5,6) and is perpendicular to the line 3x-5y=2. express in slope intercept form

Question 748222: Find the equation of the line that goes through the point (-5,6) and is perpendicular to the line 3x-5y=2. express in slope intercept form
Answer by timvanswearingen(106) (Show Source): You can put this solution on YOUR website!
First, find the slope of:

To do this, get the equation into slope-intercept form: y=mx+b

Subtract 3x from both sides:

Divide both sides by -5:

So the slope of that line is 3/5.
When finding a perpendicular slope, just flip the slope and change the sign.
So the perpendicular slope will be:

Now, you have a point the line will be going through: (-5,6) and the slope: -5/3
As its name suggests, you'll be using Point-Slope form now to find the equation of the line.

Plug the x and y from your ordered pair in for X1 and Y1. Plug in -5/3 for m:

Subtracting a negative is like adding a positive...

Now we just have to distribute, and get this into slope-intercept form (y=mx+b)

Add six to both sides:

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