SOLUTION: how does the graph of the line y=2/3x=1 differ from the graph of the line y=4x+1? a.) y=2/3x+1 is steeper than y=3x-1 b.)y=3x+1 is steeper than y=2/3x+1 c.)y=2/3x+1 and y=3x+1 d

Question 746811: how does the graph of the line y=2/3x=1 differ from the graph of the line y=4x+1?
a.) y=2/3x+1 is steeper than y=3x-1
b.)y=3x+1 is steeper than y=2/3x+1
c.)y=2/3x+1 and y=3x+1 do not differ
d.)the y-intercept of y= ex+1 is 2(1/3) unites higher than the y-intercept of y=2/3x+1
e.)the x-intercept of y=3x+1 is 2(1/3) units to the rigfht of the x-intercept of y=2/3x+1
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
first find two points for each line and graph them:

set and find
=> ...so, one point is (,)
set and find
=> ...so, other point is (,)

set and find
=> ...so, one point is (,)
set and find
=> ...so, other point is (,)
now plot these points and draw lines through

compare lines: A higher value indicates a incline.
=> a slope is
=> a slope is
a higher value than

so, the line is steeper than
answer: b.)

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