# SOLUTION: graph a)by finding the x- and y-intercept: x-3y=-6 b)x-4y=-8

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: graph a)by finding the x- and y-intercept: x-3y=-6 b)x-4y=-8      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Linear Equations, Graphs, Slope Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Linear-equations Question 74223: graph a)by finding the x- and y-intercept: x-3y=-6 b)x-4y=-8Found 2 solutions by rmromero, bucky:Answer by rmromero(383)   (Show Source): You can put this solution on YOUR website!``` graph a) by finding the x- and y-intercept : x-3y=-6 Two points determine a line.WE need two points then. The x-intercept and the y-intercept To find x-intercept , y = 0. Substitute it to x-3y=-6 x - 3(0) = -6 x = -6 First point is located (-6,0) To find y -intercept, x = 0.Substitute it to x-3y=-6 0 - 3y = -6 -3y = -6 y = 2 second point is located (0, 2) graphing time b)by using the slope and y-intercept : x-4y=-8 Slope - intercept form is y = mx + b, where m = slope and b = y-intercept we will rewrite the given equation to slope - intercept form x + 8 = 4y x 8 ___ + ___ = y 4 4 1 ___x + 2 = y 4 m = 1/4 and b = 2 The first point is located using b which is the y - intercept (0,2) Using the y -intercept, the slope help us locate the next point The numerator represents the change in y and denominator the change in x from (0,2) we move 1 unit up (up for positive) and 4 unit right (right for positive) ```Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!find the x- and y-intercept of: , x-3y=-6 and . x-4y=-8 . Think about graphing. If a point of the form (x,y) has a zero value of x, then the y value has to be on the y-axis. Similarly, if a point of the form (x,y) has a zero value for y then the value for x has to be on the x-axis. . To demonstrate these two ideas, try plotting the point (0,6) you will see that it lies on the y-axis 6 units up from the origin. This is because the x value is zero ... and that requires the corresponding value of y to be on the y-axis. . Next try plotting the point (3,0). You will go out 3 units on the x-axis but that is where you will stay because the corresponding value of y is 0. . In summary we can say that when x = 0, the corresponding value for y is on the y-axis and when y = 0, the corresponding value for x is on the x-axis. . Now go to the first equation which is: . x - 3y = -6 . If we set x equal to zero we will find the corresponding value of y that is on the y-axis. When x is zero in this equation, the equation is reduced to: . -3y = -6 . Dividing both sides by -3 results in y = 2. So our point is x = 0 and y = 2 or just (0,2) and this is on the y-axis which means that it is the y-intercept. . If we then return to the equation, but this time we set y = 0 the equation reduces to . x = -6 . because y is equal to 0, this point is on the x-axis as we discussed above. This point is (-6,0) which means that it is the x-intercept. Now you can plot the two points (0,2) and (-6,0) and these two points can be connected by a straight line running through them, and this line is the graph of the equation x - 3y = -6. . The same thing can be done with the second equation: x - 4y = -8 . First, set x = 0 and solve the equation for y. With x = 0 the equation becomes just: . -4y = -8 . Divide both sides by -4 and you get y = 2. So the point (0,2) is on the graph. It is also on the y-axis and is the y-intercept. . Then set y = 0 in the equation. When you do the equation reduces to just: . x = -8 . So the point (-8,0), which is on the x-axis is also on the graph and is the x intercept. Plot the two points (0,2) and (-8,0) and extend a line through them. This is the graph of this equation. . Hope this helps you to understand how to get the x and y intercepts from a linear equation. Just set x equal to zero to get the y intercept and next set y equal to zero to get the x intercept.