SOLUTION: Please Help
The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle.
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Question 73831This question is from textbook Beginning Algebra 1A
: Please Help
The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle.
This question is from textbook Beginning Algebra 1A
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
THE FORMULA FOR THE PERIMETER IS P=2L+2W WHERE L=LENGTH, W=WIDTH
LENGTH=2W+2
52=2(2W+2)+2W
52=4W+4+2W
52-4=6W
48=6W
W=48/6
W=8 IN. IS THE WIDTH.
THEN THE LENGTH IS:
L=2*8+2
L=16+2
L=18 IN. IS THE LENGTH.
PROOF
52=2*8+2*18
52=16+36
52=52
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