SOLUTION: find the equation of the line though (-2, -6) perpendicular to the line y= (1/3)x + 4/3

Question 731405: find the equation of the line though (-2, -6) perpendicular to the line y= (1/3)x + 4/3
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The line perpendicular to will have a slope of -3/1, because perpendicular lines in a plane have slopes which are negative reciprocals of each other.

Knowing the slope, -3, and the point which must be in this new line, (-2, -6), we can use the point-slope form for a line to write the equation and then simplify:

Point-Slope form for a line

Substituting coordinate values of the given point to be contained and also the slope,

The line is:______
RELATED QUESTIONS
An equation of the line passing thru (6,1) and perpendicular to the line y-4=2(x-3)... (answered by lynnlo)

Find the slope of any line perpendicular to the line though points (0,5) and (-3,-4)... (answered by Fombitz)

Find the equation for the line that passes through (2,-2) and that is PERPENDICULAR to... (answered by lwsshak3)

Find the equation of the line perpendicular to y = −1 through the point (3,4) (answered by ikleyn)

find an equation that satisfies the given conditions though (-1,-3) perpendicular to the (answered by Alan3354)

Find the equation of the line perpendicular to the line y+3=3(x-5) that passes through... (answered by ewatrrr)

(1)Write the slope- intercept form of the equation of the line through (-1,2)that is... (answered by Nate)

Find the equation of the tangent line to the given curves. 1. y=(7x-6)^1/3 that is... (answered by greenestamps)

Line 1. Find the equation of the line 2. Having a slope 3. Passing through 4.... (answered by ikleyn)