SOLUTION: Please help me solve, Thanks Number problems. Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin does she have?

Question 72659This question is from textbook Beginning Algebra 1A
: Please help me solve, Thanks
Number problems. Jill has $3.50 in nickels and dimes. If she has 50 coins, how
many of each type of coin does she have? This question is from textbook Beginning Algebra 1A

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Jill has $3.50 in nickels and dimes. If she has 50 coins, how
many of each type of coin does she have?
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Let number of nickels be "x"; Value of these is 5x cents
Number of dimes is "50-x" ; Value of these is 10(50-x)= 500-10x cents
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EQUATION:
value + value = 350 cents
5x+500-10x = 350
-5x = -150
x=30 (number of nickels)
50-x=20 (number of dimes)
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Cheers,
Stan H.
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