Find the equation of the line that goes through (1,-3) and is parallel to the line through y=-3x-5 



Remember:

   If the lines are parallel the slopes are the same

   Slope-intercept form of the equation y = mx + b, 

   m = slope and b = y - intercept



since the equation of the line we are looking for is parallel to y = -3x-5,

 Their slopes are the same. Therefore, the slope of the line we are looking

 for is -3.



Then the equation of the line passes through (1, -3),

we can now substitute the given m=-3, y=-3 and x = 1 to find b.



     -3 = -3(1) + b , 

     -3 = -3 + b

      0 = b



After getting the b or y-intercept, we can now find the equation of the line



 Use:   y = mx + b, m = -3 and b = 0

        y = -3x + 0

        y = -3



Graph





Look at the red line, that's the equation of the line we are looking for

Notice that it passes (1,-3) and parallel to the other line with equation

equal to y = -3x-5.



I hope you understand the topic now. 



It's me

Rachel





    

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