SOLUTION: Find the value of k so that the line containing the points (−7,−7) and (3,k) is perpendicular to the line y=−1/4x+1.
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Question 720029: Find the value of k so that the line containing the points (−7,−7) and (3,k) is perpendicular to the line y=−1/4x+1.
Found 2 solutions by josmiceli, mananth:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Any line perpendicular to the line
has a slope =
In this case the slope is , so
Now I can use the point-slope formula
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Find the value of k so that the line containing the points (−7,−7) and (3,k) is perpendicular to the line y=−1/4x+1.
y= -(1/4)x +1
slope = -(1/4)
a line perpendicular to this line will have a slope of 4 ( negative reciprocal)
m= (y2-y1)/(x2-x1)
4 = (k-(-7))/(3-(-7))
4= (k+7)/10
k+7=40
k=33
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