SOLUTION: hi I am stuck on this problem I will give you the problem then show you what I did so you can tell me where I made my mistakes. Thanks {{{(z+7/9)+1=((2z+1)/6)/18}}}
I did this..
Algebra.Com
Question 71905: hi I am stuck on this problem I will give you the problem then show you what I did so you can tell me where I made my mistakes. Thanks
I did this...
Looking forward to hearing from you.
Found 3 solutions by bucky, jim_thompson5910, ankor@dixie-net.com:
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
(z+7/9)+1={(2z+1)/6}/18
I did this...
z+7/9+1*18=2z+1/6/18*18 <--- OK
18z+126/9+18=2z+1/6 <---- OK
2z+14+18=2z+1/6*6
.
The previous step seems to be in error. One error is that you show multiplying by 6 on
one side only. But it appears that this was a typo only, and in the next step below it
appears as if you did also multiply the left side by 6. However, a significant error
seems to be that on the left side in the line I marked OK, you had 18z on the left side
and in the very next line it shows as 2z. What happened to the missing 16z?
.
12z+192-1=2z+1-1 <--- OK except the 12z should be 18z*6 = 108z
12z+191=2z
12z-12z+191=2z-12z
191=-10z <--- the right side here should be -106z
.
z=-19.1 <--- weird as is seems, the correct answer to this problem is -191/106
.
You appear to have your act together about how to do problems like this. Just that one
little mistake got you off track. Good going .... keep it up ...
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
On the second step, where you multiplied everything by 18, the left side looks good, but the right side does not. The reason you multiplied everything by 18 was to cancel out the 18 in the denominator, and it should have stopped there. Here's what it should look like
Start with given problem
The 18's on the right cancel, you dont have to worry about those anymore.
Now just solve for z
Get all z's to one side and everything else to the opposite side
approximately
Check:
This shows that this answer works
You can also graph (z+7/9)+1=((2z+1)/6)/18 by changing z to x and graphing them individually (ie y=(x+7/9)+1) and their intersection should be (-1.801887,-0.02411) which is the result we got.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
=
:
Right here you should have
:
Multiply by 6:
108z + 192 = 2z + 1
:
108z - 2z = 1 - 192
106z = -191
z = -191/106
z = -1.8
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