SOLUTION: in 2005, the precent of U.S. drivers wearing seat belts was 82%. The number of drivers wearing seat belts in 2000 was 71%. Let y be the number of drivers wearing seat belts in th
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Question 715844: in 2005, the precent of U.S. drivers wearing seat belts was 82%. The number of drivers wearing seat belts in 2000 was 71%. Let y be the number of drivers wearing seat belts in the year x where x=0 represents the year 2000.
a) Write a linear equation that models the percent of US. drivers wearing seat belts in terms of the year x.
b) Use the equation found in part (a) to predict the number of U.S. drivers wearing seat belts in the year 2009.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
in 2005, the precent of U.S. drivers wearing seat belts was 82%. The number of drivers wearing seat belts in 2000 was 71%. Let y be the number of drivers wearing seat belts in the year x where x=0 represents the year 2000.
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You have 2 points relating year and percent:
(5,82) and (0,71)
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a) Write a linear equation that models the percent of US. drivers wearing seat belts in terms of the year x.
slope = (82-71)/(5-0) = 11/5 = 2.2
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intercept = f(0) = 71
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Equation:
y = 2.2x + 71
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b) Use the equation found in part (a) to predict the number of U.S. drivers wearing seat belts in the year 2009.
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f(9) = 2.2*9+71 = 90.8%
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Cheers,
Stan H.
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