SOLUTION: Bill leaves his house for Makayla's house riding his bicycle at 8 miles per hour. At the same time, Makayla leaves her house heading toward Bill's house walking a 3 miles per hour.

Question 714083: Bill leaves his house for Makayla's house riding his bicycle at 8 miles per hour. At the same time, Makayla leaves her house heading toward Bill's house walking a 3 miles per hour.
Write a system of equations to represent the distance, d, each is from Makayla's house in hours, h. They live 8.25 miles apart.
Solve the system to determine how long they travel before meeting.
Have tried 4 times...cannot figure out how to set up the equation...I can sole it once it is set up.

I tried:

8.25=d-8h 8.25=d-3y

8.25=d-8h 8.25=d-3h

x=8.25d-3h x=8.25d-3h

8d-h=8.25 3d-h=8.25

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Bill leaves his house for Makayla's house riding his bicycle at 8 miles per hour. At the same time, Makayla leaves her house heading toward Bill's house walking a 3 miles per hour.
Write a system of equations to represent the distance, d, each is from Makayla's house in hours, h. They live 8.25 miles apart.
Solve the system to determine how long they travel before meeting.
---------------------------
There are 2 distances --> 2 equations
for Bill:
d = 8.25 - 8t, d in miles, t in hours
For Makayla:
d = 0 + 3t = 3t
---------------
They meet when they're the same distance from the house.
8.25 - 8t = 3t
11t = 8.25
t = 0.75 hours
==========================

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