SOLUTION: Im trying to find an equation of a line given the points (5, 0) and (-8,-3) but when I subtract -3-0 and -8-3 and then divide mt answer -3/-13 I don't get a whole number in the cal

Question 712226: Im trying to find an equation of a line given the points (5, 0) and (-8,-3) but when I subtract -3-0 and -8-3 and then divide mt answer -3/-13 I don't get a whole number in the calculator what do I do?? Help please.. saradepaz85@yahoo.com
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Note: is the first point . So this means that and .
Also, is the second point . So this means that and .

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Distribute

Multiply

Simplify

So the equation that goes through the points and is

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Im trying to find an equation of a line given the points (5, 0) and (-8,-3)
-----
slope = (-3-0)/(-8-5) = -3/-13 = 3/13
-----
Note: Slopes do not have to be whole numbers.
------
Form: y = mx + b
0 = (3/13)5 + b
b = -15/13
=================
Equation:
y = (3/13)x - (15/13)
========================
Cheers,
Stan
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