SOLUTION: Find the value of 'a' if a line containing the point (a, -3a) has a y-intercept of 7 and a slope of 2/3.
My work:
y = -2/3x + 7
-3a = -2/3(a) + b
Algebra.Com
Question 706713: Find the value of 'a' if a line containing the point (a, -3a) has a y-intercept of 7 and a slope of 2/3.
My work:
y = -2/3x + 7
-3a = -2/3(a) + b
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
y = -2/3x + 7 (this is correct)
-3a = -2/3(a) + 7 (when you substitute, you should get this)
.
Now, all we need to do is solve for 'a':
-3a = -2/3(a) + 7
start by multiplying both sides by 3:
3(-3a) = 3(-2/3(a) + 7)
-9a = -2a + 21
adding 2a to both sides:
-7a = 21
divide both sides by -7:
a = 21/(-7)
a = -3
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