SOLUTION: graph x=(y+1)^2-4

Question 706119: graph x=(y+1)^2-4
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
graph x=(y+1)^2-4
This is an equation of a parabola that opens right.
Its standard form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
For given equation: x=(y+1)^2-4
rewrite: (y+1)^2=(x+4)
vertex: (-4,-1)
y-intercepts
set x=0
(y+1)^2=4
y+1=�√4=�2
y=-1�2
y=-3 and 1
See graph below:
y=-1+(x+4)^.5

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