SOLUTION: word problem.
The sum of twice one number and three times another is 41. If the second is subtracted from the first, the diference is 8. what are the numbers ?
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Question 70430: word problem.
The sum of twice one number and three times another is 41. If the second is subtracted from the first, the diference is 8. what are the numbers ?
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
2X+3Y=41
X-Y=8 X=Y+8 NOW SUBSTITUTE (Y+8) FOR X & SOLVE FOR Y
2(Y+8)+3Y=41
2Y+16+3Y=41
5Y=41-16
5Y=25
Y=25/5
Y=5 ANSWER NOW SUBSTITUTE 5 FOR Y & SOLVE FOR X
X-5=8
X=8+5
X=13 ANSWER.
PROOF
2*13+3*5=41
26+15=41
41=41
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