SOLUTION: Write in slope-intercept form the equation of the line passing through the given point and perpendicular to the given line. (2,6),y=-1/2x+4 please show me all the work since I

Question 702057: Write in slope-intercept form the equation of the line passing through the given point and perpendicular to the given line. (2,6),y=-1/2x+4 please show me all the work since I have 6 similar problems
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Write in slope-intercept form the equation of the line passing through the given point and perpendicular to the given line. (2,6),y=-1/2x+4
.
First, determine slope of:
y=-1/2x+4
because the above is in the "slope-intercept" form (y=mx+b) we can see that the slope is -1/2
.
a line perpendicular must have a slope that is the "negative-reciprocal".
Therefore, slope of the new line is 2 (because -1/2 * 2 = -1)
.
For our NEW line then, we have the slope (2) and one point (2,6)
plug into the "point-slope" form:
y - y1 = m (x - x1)
y - 6 = 2(x - 2)
y - 6 = 2x - 4
y = 2x - 4 + 6
y = 2x + 2 (answer in "slope-intercept" form)

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