SOLUTION: Show that the triangle with vertices (-5,2), (-2,5), and (5,-2) is a right angle. THANKS

Question 701328: Show that the triangle with vertices (-5,2), (-2,5), and (5,-2) is a right angle. THANKS
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
first find the equation of the line passing through (,) and (,)

Solved by pluggable solver: FIND EQUATION of straight line given 2 points

hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-5, 2) and (x2, y2) = (-2, 5).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .

y=(1)x + (7)

Your graph:

than find the equation of the line passing through (,) and (,)

Solved by pluggable solver: FIND EQUATION of straight line given 2 points

hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-5, 2) and (x2, y2) = (5, -2).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .

y=(-0.4)x + (0)

Your graph:

than find the equation of the line passing through (,) and (,)

Solved by pluggable solver: FIND EQUATION of straight line given 2 points

hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, 5) and (x2, y2) = (5, -2).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .

y=(-1)x + (3)

Your graph:

now graph all three lines together:
.........a slope is
.........a slope is

.........a slope is which is negative reciprocal of ; ...so, the line and are perpendicular to each other
if two of lines perpendicular to each other, and three intersecting line form a triangle, triangle is a right angle triangle

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