SOLUTION: Find an equation of the line containing the given points (-7,-8)and (-4,-6)

Question 694421: Find an equation of the line containing the given points (-7,-8)and (-4,-6)
Found 2 solutions by jim_thompson5910, Ave:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Note: is the first point . So this means that and .
Also, is the second point . So this means that and .

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Rewrite as

Distribute

Multiply

Subtract 8 from both sides.

Combine like terms. note: If you need help with fractions, check out this solver.

So the equation that goes through the points and is

Answer by Ave(106) (Show Source): You can put this solution on YOUR website!
First find the slope
rise -8-(-6)=-2
run -7-(-4)=-3
so 2/3 is slope, then use point slope form
y-y1=slope(x-x1) pick either of the given points and plug it in to x1, y1
I'll use (-7,-8)
y-(-8)=2/3(x-(-7)) Times both sides by 3 to get rid of fraction
3y+24=2(x+7) Add a negative 24 to each side
3y=-24+2x+14 Combine like terms
3y=2x-10 Divide by 3
y=2/3x-10/3 usually written in this way (slope intercept)
standard form would be -2x+3y=-10
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