SOLUTION: find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2
Algebra.Com
Question 69429: find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2
Found 2 solutions by tutorcecilia, funmath:
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
Use the point-slope equation:
(y-y1)=m(x-x1)[plug-in the values and simplify]
(y-(-3))=(-1/2)((x-1)
y+3=-1/2x+1/2 [Solve for y]
y=-1/2x+1/2-3
y=-1/2x-5/2
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2
When give a point, (x1,y1), and a slope, m, and asked for an equation of the line, use the point-slope formula, .
(x1,y1)=(1,-3) and m=-1/2
The standard form of a line is , where A, B, and C are integers. Some books require that A be positive.
Happy Calculating!!!
RELATED QUESTIONS
Equation for the line that passes through 1,-5 and has a slope of 3 (in point-slope... (answered by josgarithmetic)
write the equation of the line in slope intercept form for the line that passes... (answered by ewatrrr)
Find the midpoint of the line segment with endpoints (-8,4) and (-2,-6)
Find the... (answered by josgarithmetic)
find the equation of the line that has a slope of -8 and passes through the point (-1,-5) (answered by drj)
What is the equation in standard form of the line which passes through (1, -3) and has a... (answered by harpazo)
Write the equation of the line that passes through (–1, 5) with a slope of 2 in standard... (answered by Maths68)
Write the equation of the line that passes through (–1, 5) with a slope of 2 in standard... (answered by Tatiana_Stebko,MathLover1)
Find the standard form of the equation of the line that passes through
(1/2, 2) and has (answered by josgarithmetic,mananth)
I need to find the linear equation in slope form of a line that passes through the point... (answered by ankor@dixie-net.com)