SOLUTION: Solve the following of linear equatins by graphing
x+2y<3
2x-3y<6
Please help
Algebra.Com
Question 69338: Solve the following of linear equatins by graphing
x+2y<3
2x-3y<6
Please help
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x+2y<3
2x-3y<6
---------------
Rewrite as:
y<(1/2)x+(3/2)
y>(2/3)x+2
------------------
You want the graph of the inequalities but you
have to first graph the EQUALITY which is the boundary
for each of the inequalities.
-----------
So graph:
y=(1/2)x+(3/2) using points (0,3/2) and (2,5/2)
and graph:
y=(2/3)x+2 using points (0,2) and (3,4)
-----------------------------------------
-----------
Shade the half-plane below the 1st line because you want
y<(1/2x)+(3/2)
---------
The intersection of these two half-planes is the solution
set for the system of equations.
Cheers,
Stan H.
Shade the half-plane above the 2nd line because you want
y>(2/3)x+2
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