SOLUTION: how do i find the slope and y intercept of an equationlike 5x+4y=23

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Question 673722: how do i find the slope and y intercept of an equationlike 5x+4y=23
Found 4 solutions by lynnlo, ReadingBoosters, Edwin McCravy, ewatrrr:
Answer by lynnlo(4176)   (Show Source): You can put this solution on YOUR website!
slope===============-5/4
y intercept===23/4

Answer by ReadingBoosters(3246)   (Show Source): You can put this solution on YOUR website!
Arrange in slope intercept form: y = mx + b
...
4y = -5x + 23
...
Divide both sides by 4
y =
...
Slope =
y intercept =
.....................
Delighted to help.
-Reading Boosters
Website: www.MyHomeworkAnswers.com
Wanting for others what we want for ourselves.

Answer by Edwin McCravy(20059)   (Show Source): You can put this solution on YOUR website!
1. Solve the equation for y to get it in the 
form  y = mx+b.

5x + 4y = 23 

Add -5x to both sides:

     4y = -5x + 23

Divide each number by 4

    y = x + 

             y = x + 

2. Compare that to

             y = mx + b

Then m =  and b = 

That means the slope is  and the y-intercept is 
the point (0,), where the graph (which is a line)
crosses the y-axis.

Edwin

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Use the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
5x+4y=23 0r y = (-5/4)x + 23/4 || m = -5/4 and 23/4 the y-intercept
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