SOLUTION: The perimeter of a rectangle is 38ft. The length is 1ft longer than the width. find the deminsions. Write a linear equations and solve the resulting sytem. Let x be the length

Question 673042: The perimeter of a rectangle is 38ft. The length is 1ft longer than the width. find the deminsions. Write a linear equations and solve the resulting sytem. Let x be the length ans y be the width
first equation 2x+2y=
write the second equation
x= y+
what is the length
what is the width
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,



The perimeter of a rectangle is 38ft.  

The length is 1ft longer than the width. 

  2x + 2y = 38ft

   x + y = 19ft    

  (y + 1) + y = 19

       2y = 18

        y = 9ft, the length.  The width x is  10ft 

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