SOLUTION: I have no clue how to solve this Graph the line that satisfies each set of conditions passes through(0,1), perpendicular to a line whose slope is 1/3

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Question 664563: I have no clue how to solve this

Graph the line that satisfies each set of conditions
passes through(0,1), perpendicular to a line whose slope is 1/3

Found 2 solutions by solver91311, MathLover1:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Perpendicular lines have negative reciprocal slopes. Take the negative reciprocal of the given slope to obtain the slope of the desired line, then use the point-slope form of an equation of a line:



where are the coordinates of the given point and is the calculated slope.

John

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Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
passes through(,),
perpendicular to a line whose slope is
if lines perpendicular, their slopes are negative reciprocals; so, your line will flip the which is and then its , and you would get ; so, you have a slope
now we can find the equation of the line that passes through(,) and has a slope

Solved by pluggable solver: FIND a line by slope and one point

What we know about the line whose equation we are trying to find out:

  • it goes through point (0, 1)

  • it has a slope of -3



First, let's draw a diagram of the coordinate system with point (0, 1) plotted with a little blue dot:



Write this down: the formula for the equation, given point and intercept a, is

(see a paragraph below explaining why this formula is correct)

Given that a=-3, and , we have the equation of the line:



Explanation: Why did we use formula ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (, ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (, ): Here, we know a, , and , and do not know b. It is easy to find out: . So, then, the equation of the line is: .

Here's the graph:



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