SOLUTION: Find an equation of the line through (6,-5) and parallel to 4x-2y+7=0.

Question 659100: Find an equation of the line through (6,-5) and parallel to 4x-2y+7=0.
Answer by nicy12(9) (Show Source): You can put this solution on YOUR website!
since the line through (6,-5) is parallel to 4x-2y+7=0, they must have same slope.
solving for the slop of 4x-2y+7=0 :
m= -A/B
m=-4/-2
m=2
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using the given point: (6,-5) and the slope 2, we can use the point-slope form for finding the equation.
(y-y1)=m(x-x1)
y+5=2(x-6)
y+5=2x-12
2x-y-17=0
the equation of a line through (6,-5) is 2x-y-17=0
i hope it helped you :)
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