Hi, 3x+2y+z=7, 5x+5y+4z=3, 3x+2y+3z=1 3x+2y+z=7 3x+2y+3z=1 || Subtract 2nd from 1st -2z = 6 z = -3 3x+ 2y = 10 ||multiply 1st EQ by 5 and subtract from 3 times the 2nd EQ 5x + 5y = 15 5y = -5 y = -1 and x = 4 and...Using 3x+2y+3z=1