SOLUTION: Find the value of K so that the graph of 21y-kx=4 and the line containing the points (5,-8) and (2,4) are parallel

Question 656303: Find the value of K so that the graph of 21y-kx=4 and the line containing the points (5,-8) and (2,4) are parallel

Answer by shweta(56) (Show Source): You can put this solution on YOUR website!
In equation: 21y-kx=4, we can find the slope m1 by framing it in the form of
y= mx+c ,where m is the slope
21y-kx=4
21y= 4+kx
21y= kx+4
y= kx/21+4/21
here m1= k/21 ...(1)
Now slope m2 of line containing the points (5,-8) ,(2,4)
m2= (y2- y1)/(x2- x1)
m2= 4-(-8)/2-5
m2= 4+8/(-3)
m2= -12/3
m2= -4 ...(2)
Since the graph and the line are parallel, m1= m2
k/21= -4
k= -4*21
k= -84
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