SOLUTION: find an equation of a line that contains the point (3,-5) and is perpendicular to x=4/-3

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Question 653195: find an equation of a line that contains the point (3,-5) and is perpendicular to x=4/-3
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
find an equation of a line that contains the point (3,-5) and is perpendicular to x=4/-3
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Any line perpendicular to x = 4/(-3) must be a horizontal line.
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The horizontal line thru (3,-5) is y = -5
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Cheers,
Stan H.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
The equation of a line with a defined slope m can also be written as follows:

you are given ; means ...->..
you can writ it in form as

Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of , you can find the perpendicular slope by this formula:

where is the perpendicular slope


So plug in the given slope to find the perpendicular slope



When you divide fractions, you multiply the first fraction (which is really ) by the reciprocal of the second



Multiply the fractions.


So the perpendicular slope is



So now we know the slope of the unknown line is (its the negative reciprocal of from the line ). Also since the unknown line goes through (3,-5), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

where m is the slope and (,) is the given point



Plug in , , and



Distribute



Multiply



Subtract from both sides to isolate y

Combine like terms

So the equation of the line that is perpendicular to and goes through (,) is


So here are the graphs of the equations and




graph of the given equation (red) and graph of the line (green) that is perpendicular to the given graph and goes through (,)



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