Hi,

Find an equation of a line that has an x intercept of 6 ,Pt(6,0)

and a y intercept of 4 , Pt(0,4)

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.

(6,0)

(0,4) m = -4/6 = -2/3   || 

Line:

 y = (-2/3)x + b  || Using (x,y) Ordered Pair Pt(0,4) to solve for b



   4 = b

 y = (-2/3)x + 4 



 

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 Find an equation of a line that has an x intercept of 6 and a y intercept of 4

--------------

For intercepts (A,0) and (0,B) --> Bx + Ay = A*B

4x + 6y = 24

2x + 3y = 12

---------

Or using the 2 points (6,0) & (0,4):

Slope m = diffy/diffx = 4/-6 = -2/3

------

y = mx + b

y = (-2/3)x + 4

------

Using determinants:

|x y 1|

|6 0 1| = 0

|0 4 1|

-----

x*(0-4) - y*(6-0) + 1*(24-0) = 0

-4x - 6y + 24 = 0

2x + 3y = 12

=================

The 1st method is quicker, but the other 2 work for any 2 points, not just intercepts.

 

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