SOLUTION: Find the distance between the points (-2,3) and (1,-1).
Algebra.Com
Question 644600: Find the distance between the points (-2,3) and (1,-1).
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Use the distance formula
d = sqrt((x2-x1)^2+(y2-y1)^2)
Remember that the two generic points are (x1, y1) and (x2, y2)
So (x1, y1) = (-2, 3), which means x1=-2 and y1=3
and (x2, y2) = (1, -1), which means x2=1 and y2=-1
So in short, x1=-2, y1=3, x2=1, and y2=-1.
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d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((1-(-2))^2+(-1-3)^2)
d = sqrt((1+2)^2+(-1-3)^2)
d = sqrt((3)^2+(-4)^2)
d = sqrt(9+16)
d = sqrt(25)
d = 5
So exact distance between the two points is 5 units.
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