SOLUTION: write slope intercept equation for the line that passes through (-7,6) and is perpendicular to -7x+9y=-2. Please show work so I can understand how it is done thank you.

Question 639851: write slope intercept equation for the line that passes through (-7,6) and is perpendicular to -7x+9y=-2. Please show work so I can understand how it is done thank you.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
write slope intercept equation for the line that passes through (-7,6) and is perpendicular to -7x+9y=-2.
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Standard form of equation for a line: y=mx+b, m=slope, b=y-intercept
Lines perpendicular to each other have slopes=negative reciprocals of each other's
Rewrite first equation into standard form:
-7x+9y=-2
9y=7x-2
y=7x/9-2/9
slope=7/9
negative reciprocal of this slope=-9/7
..
equation of 2nd line
y=-9x/7+b
solve for b using coordinates of given point (-7,6)
6=-9*-7/7+b
6=9+b
b=-3
equation of 2nd line:
y=-9x/7-3
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