SOLUTION: Please help me solve this problem.
(x-5)^ 2/3 = 16
so it's (x-5) to the 2/3 power equals 16, but I don't know how to distribute the 2/3 to continue my equation
Algebra.Com
Question 638075: Please help me solve this problem.
(x-5)^ 2/3 = 16
so it's (x-5) to the 2/3 power equals 16, but I don't know how to distribute the 2/3 to continue my equation
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Please help me solve this problem.
(x-5)^ 2/3 = 16
--------
cube both sides
(x-5)^2 = 16^3 = 4096
----
Take the sq roots
x-5 = 64
x = 69
=======
x-5 = -64
x = -59
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