SOLUTION: find the value of k so that the graph of kx+3y=4 is parallel to the line through (2,-k) and(4,-1). Please help

Question 637250: find the value of k so that the graph of kx+3y=4 is parallel to the line through (2,-k) and(4,-1). Please help
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
kx + 3y = 4 can be expressed as , therefore its slope is equal to .
The slope of the line joining the points (2, -k) and (4,-1) is equal to
.
Equate the two slopes because parallel line have equal slopes.
, multiply both sides by 6

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