Hi,



Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.

line.

Through: (-3,-3), perpendicular to y= -3x

New perpendicular Line  m = 1/3  (negative reciprocal of -3)

 y = (1/3)x + b   |Using ordered pair (x,y):(-3-3)  to solve for b

-3 = (1/3)*(-3) + b

-2 = b

 y = (1/3)x -2 

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