# SOLUTION: A RECTANGLE IS PLACED UNDER THE PARABOLIC ARCH GIVEN BY f(x)=27-3x2 BY USING A POINT (x,y) ON A PARABOLA. WRITE A FORMULA FOR THE FUNCTION A(x) THAT GIVES THE AREA OF THE RECTANGL

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: A RECTANGLE IS PLACED UNDER THE PARABOLIC ARCH GIVEN BY f(x)=27-3x2 BY USING A POINT (x,y) ON A PARABOLA. WRITE A FORMULA FOR THE FUNCTION A(x) THAT GIVES THE AREA OF THE RECTANGL      Log On

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 Question 63162: A RECTANGLE IS PLACED UNDER THE PARABOLIC ARCH GIVEN BY f(x)=27-3x2 BY USING A POINT (x,y) ON A PARABOLA. WRITE A FORMULA FOR THE FUNCTION A(x) THAT GIVES THE AREA OF THE RECTANGLE AS A FUNCTION OF THE x-COORDINATE OF THE POINT CHOSEN. Answer by ankor@dixie-net.com(15624)   (Show Source): You can put this solution on YOUR website!A RECTANGLE IS PLACED UNDER THE PARABOLIC ARCH GIVEN BY f(x)=27-3x2 BY USING A POINT (x,y) ON A PARABOLA. WRITE A FORMULA FOR THE FUNCTION A(x) THAT GIVES THE AREA OF THE RECTANGLE AS A FUNCTION OF THE x-COORDINATE OF THE POINT CHOSEN : The axis of symmetry will be at 0 : The height of the square will be y which is 27- 3x^2 : Length of the square will be 2x : A(x) = 2x(27-3x^2) : An example when x = 2, Length = 4, y = 15 (height), Area = 15*4 = 60 : A(2) = 2(2)(27 - 3(2^2) A(2) = 4(27 - 12) A(2) = 4(15) A(2) = 60 Looks kind of like this: : A graph of the area of the rectangle equation: : As you can probably see I have not done this particular problem before but got to thinking about it and this is what I came up, hope it's helpful