SOLUTION: IF f(x)=x(x+3)(x-1), USE INTERVAL NOTATION TO GIVE ALL VALUES OF x WHERE f(x)>0.

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Given a equation f(x) = x (x+3) (x-1)
For x = 0 the functionf(x) = 0,
It contradicts the condition f(x) > 0
For x =1, the function f(x)= 0
But it contradicts the condition f(x)> 0
for x =2, f(x) = 10
The condition f(x)>0 its been satisfied.
We construct the interval (1,+infinty)
Let us now consider for x = -1,
the function f(x) =4
The condition for f(X) > 0 is satisfied.
for x =-2, f(x) = 6
It satisfies f(x) > 0
For x =-3, f(x) = 0
Which contradicts the condition f(x) > 0
Therefore all the values from -1 to -2 is satisfied.
We construct the interval(-2 ,-1)
The values of "x" in interval notation can be written as
[-2, -1] U [2, infinity]