SOLUTION: DETERMINE THE VERTEX OF y=x2-8x+22.

Question 62755: DETERMINE THE VERTEX OF y=x2-8x+22.
Found 2 solutions by jai_kos, uma:
Answer by jai_kos(139) (Show Source): You can put this solution on YOUR website!

y= x2-8x+22.
The given function looks like a quadratic equation, we get a = 1, b =-8 and c = 22
The vertex is given by (-b /2a) = [ -(-8)/ 2 *1]
= [ 8 /2] = 4

The y value is given when you substitute x = 4in equation(1), we get
y = 4^2 -8*4 + 22 = 16 - 32 + 22 = 38 -32 = 6
y = 6
Now the vertex is (x ,y) = (4 ,6)
Answer by uma(370) (Show Source): You can put this solution on YOUR website!
y = x^2 - 8x + 22

This represents a parabola of the standard form y = ax^2 + bx + c
The x co-ordinate of the vertex is given by -b/2a
Thus the x co-ordinate = -(-8)/2*1
= 8/2
= 4
Substituting x = 4 in the given equation,
y = 4^2 - 8*4 + 22
= 16 - 32 + 22
= 6
So the vertex of the given parabola is (4,6)
Good Luck!!!
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