SOLUTION: Write an equation of the line containing the points (2, -3) and (4, 5).

Question 625861: Write an equation of the line containing the points (2, -3) and (4, 5).
Found 2 solutions by jim_thompson5910, lenny460:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

First let's find the slope of the line through the points and

Note: is the first point . So this means that and .
Also, is the second point . So this means that and .

Start with the slope formula.

Plug in , , , and

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points and is

Now let's use the point slope formula:

Start with the point slope formula

Plug in , , and

Rewrite as

Distribute

Multiply

Subtract 3 from both sides.

Combine like terms.

So the equation that goes through the points and is

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Answer by lenny460(1073) (Show Source): You can put this solution on YOUR website!
Plot the straight line graph with the following points:
(2,-3)
(4,5)
From the above straight line graph:
the y-intercept is -11

Now let's find the Slope (m)
(y2 - y2)/(x2 - x1)
= (-3 - 5)/(2 - 4)
= -3 - 5 = -8
= 2 - 4 = -2
Therefore:
-8/-2 = 8/2 = 4
The Slope (m) = 4

The other method:
(5 - (-3)/(4 -2)
5 - (-3) = 5 + 3 = 8
4 - 2 = 2
8/2 = 4
The Slope (m) = 4

We now use the formula:
y = mx + b
m = slope = 4
b = y-intercept = -11
Therefore:
y = 4x - 11

The Answer:

y = 4x - 11

obuong3@aol.com
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