SOLUTION: the perimeter of a rectangle is 30ft. The length is 11 ft longer than width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the le

Question 625016: the perimeter of a rectangle is 30ft. The length is 11 ft longer than width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width.
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
Per = 2(x+y)=30
x = y+11
Then:
2(y+11+y)=30
2y+11=15
2y=4
y=2
x=13
Answer: Width = 2 and Lenght= 13
If you have any doubt or if you have more problems my e-mail is:
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