SOLUTION: Hello,
At a total lost with this one.
Can you pls complete the given ordered pairs so that each ordered pair satisfies the given equiation?
(0, ),( ,0),(-6, ),( ,5),2x + 3y = 5
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Question 62203This question is from textbook Algebra for college students
: Hello,
At a total lost with this one.
Can you pls complete the given ordered pairs so that each ordered pair satisfies the given equiation?
(0, ),( ,0),(-6, ),( ,5),2x + 3y = 5
Thank you for your time in this matter.
This question is from textbook Algebra for college students
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Can you pls complete the given ordered pairs so that each ordered pair satisfies the given equiation?
:
Once you understand this it will be easy for you to do:
:
(0, ),( ,0),(-6, ),( ,5), 2x + 3y = 5
:
In the first ordered pair the give x = 0, want you to find y:
In the equation 2x + 3y = 5, replace x with 0 and solve for y:
3(0) + 3y = 5
0 + 3y = 5
y = 5/3
So the 1st ordered pair: (0,5/3)
:
On the 2nd ordered pair: (_,0), exchange 0 for y in the equation:
2x + 3(0) = 5
2x + 0 = 5
x = 5/2
The 2nd ordered pair: (5/2,0), in decimal it would be (2.5,0)
:
The 3rd ordered pair (-6,_), substitute -6 for x, find y:
2(-6) + 3y = 5
-12 + 3y = 5
3y = 5 + 12
3y = 17
y = 17/3 or decimal 5.67
The 3rd ordered pair (-6,5.67)
:
The 4th ordered pair: (_,5), Substitute 5 for y and find x:
2x + 3(5) = 5
2x + 15 = 5
2x = 5 - 15
x = -10/2
x = -5
The 4th ordered pair: (-5,+5)
:
Do you get the idea now?
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