SOLUTION: Find the equation for the line that passes through the point (3,5), and that is parallel to the line with the equation (y-1=-2/3(x-1). Note: -2/3 is suppose to be in fraction

Question 621180: Find the equation for the line that passes through the point (3,5), and that is parallel to the line with the equation (y-1=-2/3(x-1).
Note: -2/3 is suppose to be in fraction form, so it's -2 OVER 3. NOT DIVIDED
thanks,
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Find the equation for the line that passes through the point (3,5), and that is parallel to the line with the equation (y-1=-2/3(x-1).
.
Note: a fraction (a/b) can be considered as "a divided by b".
.
Slope of:
y-1=-2/3(x-1)
is -2/3
.
A line parallel will have the same slope.
So, now we have:
m (slope) is -2/3
and one point (3,5)
.
Plug into "point-slope" form:
y - y1 = m(x -x1)
y - 5 = (-2/3)(x - 3)
y - 5 = (-2/3)x - (-2/3)3
y - 5 = (-2/3)x - (-2)
y - 5 = (-2/3)x + 2
y = (-2/3)x + 7 (this is what they're looking for in "slope-intercept" form)

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