Hi

Using the standard slope-intercept form for an equation of a line y = mx + b 

 where m is the slope and b the y-intercept.  

line perpendicular to y =  1/3x + 5 through (2, 1)

Note: slopes of perpendicular lines  are negative reciprocals of one another

New Line:

 y = -3x + b   ||using Pt(2,1) to solve for b

 1 = -6 + b

 7 = b

 y = -3x + 7



 

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