# SOLUTION: Find the equation of the straight line through the point (-1,-7) and parallel to y= 2x + 3

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 Click here to see ALL problems on Linear-equations Question 611894: Find the equation of the straight line through the point (-1,-7) and parallel to y= 2x + 3Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Equation of the line slope-intercept form y=mx+b Equation of the Given line y=2x+3 Compare with the equation of line slope-intercept form Slope of the given = m = 2 Since lines are parallel their slope will be same Slope of the required line = m = 2 Point (-1, -7) We have a point and slope we can get easily the require line equation. Use Equation of the line point-slope form m = y2-y1/x2-x1 Put the values in above equation, we have 2=(y-(-7))/(x-(-1)) 2=(y+7))/(x+1)) 2(x+1)=y+7 2x+2=y+7 2x+2-7=y 2x-5=y y=2x-5 Above equation is the equation of the required line Graph ----- y=2x+3 Given line (Red) y=2x-5 Required line (Green)