Hi

Using the standard slope-intercept form for an equation of a line y = mx + b 

 where m is the slope and b the y-intercept 

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equation of a line that is perpendicular to the line y=-2/5x-5 and passes through the point 6,1

New Line:  slope = 5/2 (Negative reciprocal of -2/5)

 y = (5/2)x + b

 1 = (5/2)6 + b

 -14 = b

 y = (5/2)x -14 

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