# SOLUTION: Write the slope intercept equation for the line that passes through (14,-2) and is perpendicular to 7x-10y=18

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: Write the slope intercept equation for the line that passes through (14,-2) and is perpendicular to 7x-10y=18      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Algebra: Linear Equations, Graphs, Slope Solvers Lessons Answers archive Quiz In Depth

 Question 604765: Write the slope intercept equation for the line that passes through (14,-2) and is perpendicular to 7x-10y=18Answer by alicealc(281)   (Show Source): You can put this solution on YOUR website!7x - 10y = 18 7x - 18 = 10y (divide all by 10) 7/10 x - 18/10 = y the slope for this line is 7/10 2 lines are perpendicular if slope line 1 * slope line 2 = -1 7/10 * slope line 2 = -1 slope line 2 = -1 * 10/7 = -10/7 line equation that has slope of m and passes through (x1, y1): y - y1 = m*(x - x1) this line has the slope of -10/7 and passes through (14, -2), so: y - (-2) = -10/7 * (x - 14) y + 2 = -10/7 x + 140/7 y + 2 = -10/7 x + 20 y = -10/7 x + 20 - 2 y = -10/7 x + 18