SOLUTION: can you show me how can i make this out of linear inequalities by graphing. x � 3y > 6 3x + 2y

SOLUTION: can you show me how can i make this out of linear inequalities by graphing. x � 3y > 6 3x + 2y > 12

Question 60330: can you show me how can i make this out of linear inequalities by graphing.
x � 3y > 6
3x + 2y > 12

Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
x � 3y > 6 [Re-write in the slope-intercept format by solving for y]
-3y>-x+6
-3y/-3<-x/-3+6/-3 [Switch the sign when multiplying or dividing by a negative number]
.
y<1/3x-2
The y-intercept is (0, -2)
The x-intercept is (6, 0)
The slope is (1/3)
Graphing: Draw a dashed boundary line and shade all of the points below the dashed line.

.
3x + 2y > 12 [Re-write in the slope-intercept format by solving for y]
2y>-3x+12
2y/2>-3/2x+12/2
y>-3/2x+6
The y-intercept is (0,6)
The x-intercept is (4, 0)
Graphing: Draw a dashed line and shade all of the points above the dahsed line.
.

.
Graph both lines together to get the area of overlap. The area of overlap represents all of the points that the two lines have in common.
.

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